All questions

A question about a recipe: Sara's "Granola Bars"

F9fe21fd 556d 417f 8a88 4cf54f80d64a  051611f 493

where can you purchase "almond butter"?

asked by sueellen about 7 years ago

Are you channeling your best self with this comment? (If you're not sure, check out our Code of Conduct.)

5 answers 1693 views
drbabs
drbabs

Barbara is a trusted source on General Cooking.

added about 7 years ago

I get it at Trader Joe's. Do you have a Trader Joe's near you? I imagine a health food store would have it as well.

Are you channeling your best self with this comment? (If you're not sure, check out our Code of Conduct.)

Amanda Hesser
Amanda Hesser

Amanda is a co-founder of Food52.

added about 7 years ago

I usually find it at health food stores and Whole Foods.

Are you channeling your best self with this comment? (If you're not sure, check out our Code of Conduct.)

SKK
SKK
added about 7 years ago

Regular grocery stores also carry almond butter.

Are you channeling your best self with this comment? (If you're not sure, check out our Code of Conduct.)

Merrill Stubbs
Merrill Stubbs

Merrill is a co-founder of Food52.

added about 7 years ago

If you can't find almond butter, peanut butter or cashew butter would also work.

Are you channeling your best self with this comment? (If you're not sure, check out our Code of Conduct.)

lil'jinx
added about 7 years ago

If you have a food processor, making almond butter is very easy. Roast whole almonds at 350 until they smell toasty, about 10 minutes. Cool them down until warm, put into food processor, and let it go - it will take a while, first becoming mealy, then pasty - I usually stop when the oil starts to exude or separate. If you want a smoother texture, which you might for a recipe such as the granola bars, you can add a bit of walnut oil or a neutral oil like grapeseed, canola, etc., while the processor is going. This works for all kinds of nuts and is delish.

Are you channeling your best self with this comment? (If you're not sure, check out our Code of Conduct.)